设f(x)是定义在R上的偶函数,当0≤x≤π/2时,f(x)=cos(x π/3)-1/2 ,且f(x π)=f(x设f(x)是定义在R上的偶函数,当0≤x≤π/2时,f(x)=cos(x+π/3)-1/2 ,且f(x+π)=f(x).1)试写出f(x)在(-π/2,π/2)上的解析式2)求f(31π/6
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![设f(x)是定义在R上的偶函数,当0≤x≤π/2时,f(x)=cos(x π/3)-1/2 ,且f(x π)=f(x设f(x)是定义在R上的偶函数,当0≤x≤π/2时,f(x)=cos(x+π/3)-1/2 ,且f(x+π)=f(x).1)试写出f(x)在(-π/2,π/2)上的解析式2)求f(31π/6](/uploads/image/z/10264285-37-5.jpg?t=%E8%AE%BEf%28x%29%E6%98%AF%E5%AE%9A%E4%B9%89%E5%9C%A8R%E4%B8%8A%E7%9A%84%E5%81%B6%E5%87%BD%E6%95%B0%2C%E5%BD%930%E2%89%A4x%E2%89%A4%CF%80%2F2%E6%97%B6%2Cf%28x%29%3Dcos%28x+%CF%80%2F3%29-1%2F2+%2C%E4%B8%94f%28x+%CF%80%29%3Df%28x%E8%AE%BEf%28x%29%E6%98%AF%E5%AE%9A%E4%B9%89%E5%9C%A8R%E4%B8%8A%E7%9A%84%E5%81%B6%E5%87%BD%E6%95%B0%2C%E5%BD%930%E2%89%A4x%E2%89%A4%CF%80%2F2%E6%97%B6%2Cf%28x%29%3Dcos%28x%2B%CF%80%2F3%29-1%2F2+%2C%E4%B8%94f%28x%2B%CF%80%29%3Df%28x%29.1%29%E8%AF%95%E5%86%99%E5%87%BAf%28x%29%E5%9C%A8%EF%BC%88-%CF%80%2F2%2C%CF%80%2F2%EF%BC%89%E4%B8%8A%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F2%EF%BC%89%E6%B1%82f%2831%CF%80%2F6)
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