Two vectors have equal magnitude,and their scalar product is one-third the square of their magnitud

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Two vectors have equal magnitude,and their scalar product is one-third the square of their magnitud
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Two vectors have equal magnitude,and their scalar product is one-third the square of their magnitud
Two vectors have equal magnitude,and their scalar product is one-third the square of their magnitud

Two vectors have equal magnitude,and their scalar product is one-third the square of their magnitud
The question is not complete,I guess it was asking for the angle between the 2 vectors:
scalar product = a^2/3 = a*a*cosθ = a^2cosθ
cosθ = 1/3
θ = 70.52°