若x∈{y│y=x^2-2x+2},则1/(x+1)的取值范围是?知道了y≥1,为什么得出x≥1?
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若x∈{y│y=x^2-2x+2},则1/(x+1)的取值范围是?知道了y≥1,为什么得出x≥1?
若x∈{y│y=x^2-2x+2},则1/(x+1)的取值范围是?
知道了y≥1,为什么得出x≥1?
若x∈{y│y=x^2-2x+2},则1/(x+1)的取值范围是?知道了y≥1,为什么得出x≥1?
{y│y=x^2-2x+2}={y|y=(y-1)^2+1}={y|y≥1}
∴x∈{y│y=x^2-2x+2}即x∈{x|x≥1}
∴1/(x+1)≤1/2
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