(x+y)*x^2/x^2-y^2+y^2/x-y-(2x^2y-2xy^2)/(x^2-2xy+y^2)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/16 08:39:43
(x+y)*x^2/x^2-y^2+y^2/x-y-(2x^2y-2xy^2)/(x^2-2xy+y^2)
x)ӨЮԪ3b8#J[RW(RkTI iM"}2uPb=t 8iGۓ@6 ( Tli u>4GS.䁴.D b@:L].,LH^Upda F 16`Ӟi5( CFPPh 6===n]yӍSiY0܁?Ua(ǖ==H2$K

(x+y)*x^2/x^2-y^2+y^2/x-y-(2x^2y-2xy^2)/(x^2-2xy+y^2)
(x+y)*x^2/x^2-y^2+y^2/x-y-(2x^2y-2xy^2)/(x^2-2xy+y^2)

(x+y)*x^2/x^2-y^2+y^2/x-y-(2x^2y-2xy^2)/(x^2-2xy+y^2)
(1)(x+y)·x^2-y^2分之x^2 +x-y分之y^2 -(2x^2y-2xy^2)÷(x^2-2xy+y^2)
=(x+y)*x²/(x+y)(x-y)+y²/(x-y)-2xy(x-y)/(x-y)²
=x²/(x-y)+y²/(x-y)-2xy/(x-y)
=(x²+y²-2xy)/(x-y)
=(x-y)²/(x-y)
=x-y

化简 ( x+y)·x^2-y^2分之x^2 +x-y分之y^2 -(2x^2y-2xy^2)÷(x^2-2xy+y^2)
=(x+y)*x²/(x+y)(x-y)+y²/(x-y)-2xy(x-y)/(x-y)²
=x²/(x-y)+y²/(x-y)-2...

全部展开

化简 ( x+y)·x^2-y^2分之x^2 +x-y分之y^2 -(2x^2y-2xy^2)÷(x^2-2xy+y^2)
=(x+y)*x²/(x+y)(x-y)+y²/(x-y)-2xy(x-y)/(x-y)²
=x²/(x-y)+y²/(x-y)-2xy/(x-y)
=(x²+y²-2xy)/(x-y)
=(x-y)²/(x-y)
=x-y

收起