杭电ACM 1005 javaA number sequence is defined as follows:f(1) = 1,f(2) = 1,f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.Given A,B,and n,you are to calculate the value of f(n).The input consists of multiple test cases.Each test case contains 3 integer

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杭电ACM 1005 javaA number sequence is defined as follows:f(1) = 1,f(2) = 1,f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.Given A,B,and n,you are to calculate the value of f(n).The input consists of multiple test cases.Each test case contains 3 integer
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杭电ACM 1005 javaA number sequence is defined as follows:f(1) = 1,f(2) = 1,f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.Given A,B,and n,you are to calculate the value of f(n).The input consists of multiple test cases.Each test case contains 3 integer
杭电ACM 1005 java
A number sequence is defined as follows:
f(1) = 1,f(2) = 1,f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.
Given A,B,and n,you are to calculate the value of f(n).
The input consists of multiple test cases.Each test case contains 3 integers A,B and n on a single line (1

杭电ACM 1005 javaA number sequence is defined as follows:f(1) = 1,f(2) = 1,f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.Given A,B,and n,you are to calculate the value of f(n).The input consists of multiple test cases.Each test case contains 3 integer
if (a < 1 && a > 1000 && b < 1 && b > 1000 && b < 1 && a > 100000000)
System.exit(0);
这句你用的是& 不对 还有就是你这个做法不行 BigInteger f[] = new BigInteger[n]; 当n=100000000时开不了这么大的数组 时间复杂度也不行 必定超时