作业帮1/1x2+1/2x3+1/3x4+```````+1/1999x2000=?
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1/1x2+1/2x3+1/3x4+```````+1/1999x2000=?
1/1x2+1/2x3+1/3x4+```````+1/1999x2000=?
1/1x2+1/2x3+1/3x4+```````+1/1999x2000=?
原式=（1-1/2）+（1/2-1/3）+（1/3-1/4）+.（1/1998-1/1999）+（1/1999-1/2000） =1-1/2000=1999/2000
1/（1x2）+1/（2x3）+1/（3x4）+1/（4x5）+......+1/（1999x2000） =1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+....-1/1998+1/1998-1/1999+1/1999-1/2000 =1-1/2000 =1999/2000 希望帮到你o(∩_∩)o 不懂追问哦
用克拉默法则解下列方程组 x1-2x2+3x3-4x4=4 x2-x3+x4=-3 x1+3x2+2x4=1 -7x2+3x3+x4=3x1-2x2+3x3-4x4=4x2-x3+x4=-3 x1+3x2+2x4=1 -7x2+3x3+x4=3
因式分解：x4+x3+2x2 +x+1
解方程组X1-2x2+3x3-x4=1,3x1-x2+5x3-3x4=2,2x1+x2+2x3-2x4=3
x1+5x2-x3-x4=-1x1-2x2+x3+3x4=33x1+8x2-x3+x4=1
写出方程组2*x1+x2-x3+x4=1,x1+2*x2+x3-x4=2,x1+x2+2*x3+x4=3的通解?
求非齐次线方程组的通解 ：2x1+x2-x3+x4=1 x1+2x2+x3-x4=2 x1+x2+2x3+x4=3
具体写出方程组：2x1+x2-x3+x4=1;x1+2x2+x3-x4=2;x1+x2+2x3+x4=3的通解
解一道方程组x1+x2+x3=5,x2+x3+x4=1,x3+x4+x5=-5,x4+x5+x1=-3,x5+x1+x2=2
用初等行变换来解下列线性方程组（1）2x1-x2+3x3=3 3x1+x2-5x3=0 4x1-x2+x3=3 x1+3x2-13x3=-6(2) x1-2x2+x3+x4=1 x1-2x2+x3-x4=-1 x1-2x2+x3-5x4=5(3) x1-x2+x3-x4=1 x1-x2-x3+x4=0 x1-x2-2x3+2x4=-1/2
1X2+2X3+3X4+.NX(N+1)
1X2+2X3+3X4+.NX(N+1)规律
1x2+2x3+3x4+.+2011x2012
1x2+2x3+3x4+4x5+.+15x16
1x2+2x3+3x4+.+100x101=
1x2+2x3+3x4+.+100x101=?结果
1x1!+2x2!+3x3!+4x4!.nxn!
1X2+2x3+3x4+……+2013x2014
1x2+2x3+3x4+.+19x20