数列{an}满足a1=a>0,an+1=根号a(n+2)1)若数列{an}既是ap又是gp,求a2)求a的取值范围,使得对于一切自然数n都有a(n+1)>an

数列an满足an+1=根号(an^2+1)+an,a1=a>0,求an通项公式 数列{an)满足an=4a(n-1)+3,a1=0,求数列{an}的通项公式 数列[An]满足An+1-An+3=0,且A1=-5.求An. 已知数列满足a1=1/2,an+1=2an/(an+1),求a1,a2已知数列满足a1=1/2,a(n+1)=2an/(an+1),求a1,a2;证明0 已知数列{an}满足a(n+1)=an+n,a1=1,则an= 数列{an}满足a1=a,an+1=1+1/an.若3/2 数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010 已知数列{an}满足a(n+1)=an+lg2,a1=1,求an 数列[An]满足a1=2,a（n+1）=3an-2 求an 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 数列An满足A1=0,A(n+1)=(An-√3)/(√3An+1)则A2009= 已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an 数列an满足a1=0,An+1=an+2n求a2009 已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an 数列{an}满足:a1=1,an>0,an+1^2-an^2=1,那么an 已知数列｛an｝满足a1=1,an+1 -an+2an+1•an=0求通项 数列{an}满足:a1=1,an>0,an+1^2-an^2=1,那么an