已知数列{An}满足A(n+1)=An+n且A61=2000则A1=?
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已知数列{An}满足A(n+1)=An+n且A61=2000则A1=?
已知数列{An}满足A(n+1)=An+n且A61=2000则A1=?
已知数列{An}满足A(n+1)=An+n且A61=2000则A1=?
a(n+1)=a(n)+n=a(n)+[n(n+1)-(n-1)n]/2,
a(n+1)-n(n+1)/2=a(n)-(n-1)n/2=...=a(1)-0=a(1),
a(1)=a(61)-60*61/2=2000-30*61=2000-1830=170
A1=170 通项 是 N(n-1)+170
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