(x+y-5)的绝对值+(xy-6)^2=0,求x^2+y^2

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(x+y-5)的绝对值+(xy-6)^2=0,求x^2+y^2
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(x+y-5)的绝对值+(xy-6)^2=0,求x^2+y^2
(x+y-5)的绝对值+(xy-6)^2=0,求x^2+y^2

(x+y-5)的绝对值+(xy-6)^2=0,求x^2+y^2
(x+y-5)的绝对值+(xy-6)^2=0,
x+y-5=0
xy-6=0
x+y=5 xy=6
x²+y²
=x²+2xy+y²-2xy
=(x+y)²-2xy
=25-6×2
=13

(x+y-5)的绝对值+(xy-6)^2=0
则 x+y-5=0
xy=6
解得x=2,y=3 或者y=2,x=3
x^2+y^2
代入 可以得出 13