在三角形ABC中,A、B为锐角,且cos2A=3/5,sinB=(根号10)/10.求A+B.若a-b=根号2-1,求a、b、c的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/25 14:53:03
![在三角形ABC中,A、B为锐角,且cos2A=3/5,sinB=(根号10)/10.求A+B.若a-b=根号2-1,求a、b、c的值](/uploads/image/z/1038763-19-3.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CA%E3%80%81B%E4%B8%BA%E9%94%90%E8%A7%92%2C%E4%B8%94cos2A%3D3%2F5%2CsinB%3D%EF%BC%88%E6%A0%B9%E5%8F%B710%EF%BC%89%2F10.%E6%B1%82A%2BB.%E8%8B%A5a-b%3D%E6%A0%B9%E5%8F%B72-1%2C%E6%B1%82a%E3%80%81b%E3%80%81c%E7%9A%84%E5%80%BC)
xUMO@+9U YCJF3">BF҂JŇB%))!)owm^);f̦\Gpb;AذoAⶵ1ufd_,8lÝsvFpbaYNa~5=I
]dox3,{/Jj?u;~Е(mZ4bE%,^8/a;%L`УfT!)P يM F@tE FL~y13mJpkAJTmcsiƮvxxo֗]"Yz1veW$#RVDLUb%Ѵv*OW'T(:NRb>sU{84xqLgb/ỹO%YjPRhꀰ
s=p
,.^nӧrYHc@[&-
8u3G#L҇)#ƀ¦u̪-F4Y1zHkRudcs2]B!:RkuPZAN