如图,在△ABC中,∠ABC和∠ACB的平分线相交于点O,过点O作EF‖BC交AB于E,交AC于F,过点O作OD⊥AC于D.下列四个结论:①∠BOC=90º+ 1 2∠A;②EF不可能是△ABC的中位线;③设OD=m,AE+AF=n,则S△AEF
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![如图,在△ABC中,∠ABC和∠ACB的平分线相交于点O,过点O作EF‖BC交AB于E,交AC于F,过点O作OD⊥AC于D.下列四个结论:①∠BOC=90º+ 1 2∠A;②EF不可能是△ABC的中位线;③设OD=m,AE+AF=n,则S△AEF](/uploads/image/z/10398129-33-9.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0ABC%E5%92%8C%E2%88%A0ACB%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9O%2C%E8%BF%87%E7%82%B9O%E4%BD%9CEF%E2%80%96BC%E4%BA%A4AB%E4%BA%8EE%2C%E4%BA%A4AC%E4%BA%8EF%2C%E8%BF%87%E7%82%B9O%E4%BD%9COD%E2%8A%A5AC%E4%BA%8ED%EF%BC%8E%E4%B8%8B%E5%88%97%E5%9B%9B%E4%B8%AA%E7%BB%93%E8%AE%BA%EF%BC%9A%E2%91%A0%E2%88%A0BOC%EF%BC%9D90%26ordm%3B%EF%BC%8B+1+2%E2%88%A0A%EF%BC%9B%E2%91%A1EF%E4%B8%8D%E5%8F%AF%E8%83%BD%E6%98%AF%E2%96%B3ABC%E7%9A%84%E4%B8%AD%E4%BD%8D%E7%BA%BF%EF%BC%9B%E2%91%A2%E8%AE%BEOD%EF%BC%9Dm%2CAE%EF%BC%8BAF%EF%BC%9Dn%2C%E5%88%99S%E2%96%B3AEF)
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