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来源：学生作业帮助网 编辑：作业帮 时间：2024/08/03 03:50:12
RT
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证明：
∠CGH
=90°-1/2∠ACB
=90°-1/2[180°-（∠ABC+∠CAB）]
=1/2（∠ABC+∠CAB）
=1/2∠ABC+1/2∠CAB
=∠ABG+∠BAG
又∵∠ABG+∠BAG=∠BGD
∴∠CGH=∠BGD
得证!

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