已知△ABC为等边三角形,点D为直线BC上一动点(点D不与B、C重合),AB为边作菱形ADEF,∠DAF=60°,连接CF(1)证明AC=CF+CD(2)当D在BC的延长线且其他条件不变时,那么AC=CF+CD是否成立?若不成立,写出三边的
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/27 15:31:06
![已知△ABC为等边三角形,点D为直线BC上一动点(点D不与B、C重合),AB为边作菱形ADEF,∠DAF=60°,连接CF(1)证明AC=CF+CD(2)当D在BC的延长线且其他条件不变时,那么AC=CF+CD是否成立?若不成立,写出三边的](/uploads/image/z/10412006-14-6.jpg?t=%E5%B7%B2%E7%9F%A5%E2%96%B3ABC%E4%B8%BA%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E7%82%B9D%E4%B8%BA%E7%9B%B4%E7%BA%BFBC%E4%B8%8A%E4%B8%80%E5%8A%A8%E7%82%B9%EF%BC%88%E7%82%B9D%E4%B8%8D%E4%B8%8EB%E3%80%81C%E9%87%8D%E5%90%88%EF%BC%89%2CAB%E4%B8%BA%E8%BE%B9%E4%BD%9C%E8%8F%B1%E5%BD%A2ADEF%2C%E2%88%A0DAF%3D60%C2%B0%2C%E8%BF%9E%E6%8E%A5CF%281%29%E8%AF%81%E6%98%8EAC%3DCF%2BCD%282%29%E5%BD%93D%E5%9C%A8BC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%94%E5%85%B6%E4%BB%96%E6%9D%A1%E4%BB%B6%E4%B8%8D%E5%8F%98%E6%97%B6%2C%E9%82%A3%E4%B9%88AC%3DCF%2BCD%E6%98%AF%E5%90%A6%E6%88%90%E7%AB%8B%3F%E8%8B%A5%E4%B8%8D%E6%88%90%E7%AB%8B%2C%E5%86%99%E5%87%BA%E4%B8%89%E8%BE%B9%E7%9A%84)
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