化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=

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化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=
x){3< 6j&ko7A BIJI*'[~ e6 ] _ 1*a&\DQD"F 1 

化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=
化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=

化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=
sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)
=(-sinα)*(-sinα)+(-cosα)*(-cosα)
=(sinα)^2+(cosα)^2=1