求不定积分(1/x根号x^2-1)dx

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/27 20:07:46
求不定积分(1/x根号x^2-1)dx
x){Ɏާf=_iG=W<[i8#]C͔ "}"Uِbj0v9[LqnX2'ku+tm Vۀ9E g<=OhcUd [{zR`ļ**+u]cFf P% +TUP@qt14$slo5*4Qŀ! (

求不定积分(1/x根号x^2-1)dx
求不定积分(1/x根号x^2-1)dx

求不定积分(1/x根号x^2-1)dx
S(1/x根号x^2-1)dx=S(1/x根号x^2)dx-S(1)dx=ln|x|x||+C-x-C

arccos 1/x的绝对值+C

令x = secz,dx = secztanz dz
∫ 1/[x√(x² - 1)] dx
= ∫ 1/[secz · √(sec²z - 1)] · secztanz dz
= ∫ 1/[secz · tanz] · secztanz dz
= ∫ dz
= z + C
= arcsec(x) + C
= arccos(1/x) + C