y=log(1/2)(x^2+2x-3) 的递增区间 (1/2是底数)
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y=log(1/2)(x^2+2x-3) 的递增区间 (1/2是底数)
y=log(1/2)(x^2+2x-3) 的递增区间 (1/2是底数)
y=log(1/2)(x^2+2x-3) 的递增区间 (1/2是底数)
x^2+2x-3=0
x=-3或x=1
log(1/2)是随着x^2+2x-3的增大而减小,随着该函数的减小而递增
所以只要写出该函数的递减区间即可
因为该函数值必须为正的,
所以函数的递减区间为负无穷大到1,且1不取;
1的时候函数值为0
所以y=log(1/2)(x^2+2x-3)递增区间为(负无穷大,1)
(由于找不到夫无穷大的符号表示所以用中文表示)
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