作业帮计算:cos45°·(-1/2)^-2-(2√2-√3)^0+绝对值-√32+1/√2-1
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/24 19:19:49
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计算:cos45°·(-1/2)^-2-(2√2-√3)^0+绝对值-√32+1/√2-1
计算:cos45°·(-1/2)^-2-(2√2-√3)^0+绝对值-√32+1/√2-1
计算:cos45°·(-1/2)^-2-(2√2-√3)^0+绝对值-√32+1/√2-1
:cos45°·(-1/2)^-2-(2√2-√3)^0+绝对值-√32+1/√2-1
=√2/2*4-1+|-4√2+√2/2-1|
=2√2-1+7√2/2-1
=3√2/2-2
=√2/2*1/4-2-1+3√2+1
=√2/8+3√2-2
=25√2/8-2
cos45°·(-1/2)^-2-(2√2-√3)^0+∣-√32∣+1/(√2-1)
=√2/2·(-2)^2-1+∣-4√2∣+(√2+1)/(√2-1)(√2+1)
=√2/2·4-1+4√2+√2+1
=2√2+4√2+√2
=7√2
cos45°·(-1/2)^-2-(2√2-√3)^0+绝对值-√32+1/√2-1
=√2/2.4-1+(4√2-1)/(√2-1)
=2√2-1+(4√2-1)(√2+1)/(√2-1)(√2+1)
=2√2-1+(8+4√2-1-√2)
=2√2-1+7+3√2
=5√2+6
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计算:cos45°·(-1/2)^-2-(2√2-√3)^0+绝对值-√32+1/√2-1
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