my first letter is in 'tea' ,not in 'sea' my second letter is in 'those' ,not in 'these' my third请才醋意中绿色食品。列算式,并作答。甲乙两队同时合修一条公路,修完是甲对修了五分之三,如果甲独修7天完
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![my first letter is in 'tea' ,not in 'sea' my second letter is in 'those' ,not in 'these' my third请才醋意中绿色食品。列算式,并作答。甲乙两队同时合修一条公路,修完是甲对修了五分之三,如果甲独修7天完](/uploads/image/z/10579942-46-2.jpg?t=my+first+letter+is+in+%27tea%27+%2Cnot+in+%27sea%27+my+second+letter+is+in+%27those%27+%2Cnot+in+%27these%27+my+third%E8%AF%B7%E6%89%8D%E9%86%8B%E6%84%8F%E4%B8%AD%E7%BB%BF%E8%89%B2%E9%A3%9F%E5%93%81%E3%80%82%E5%88%97%E7%AE%97%E5%BC%8F%EF%BC%8C%E5%B9%B6%E4%BD%9C%E7%AD%94%E3%80%82%E7%94%B2%E4%B9%99%E4%B8%A4%E9%98%9F%E5%90%8C%E6%97%B6%E5%90%88%E4%BF%AE%E4%B8%80%E6%9D%A1%E5%85%AC%E8%B7%AF%EF%BC%8C%E4%BF%AE%E5%AE%8C%E6%98%AF%E7%94%B2%E5%AF%B9%E4%BF%AE%E4%BA%86%E4%BA%94%E5%88%86%E4%B9%8B%E4%B8%89%EF%BC%8C%E5%A6%82%E6%9E%9C%E7%94%B2%E7%8B%AC%E4%BF%AE7%E5%A4%A9%E5%AE%8C)
my first letter is in 'tea' ,not in 'sea' my second letter is in 'those' ,not in 'these' my third请才醋意中绿色食品。列算式,并作答。甲乙两队同时合修一条公路,修完是甲对修了五分之三,如果甲独修7天完
my first letter is in 'tea' ,not in 'sea' my second letter is in 'those' ,not in 'these' my third
请才醋意中绿色食品。
列算式,并作答。
甲乙两队同时合修一条公路,修完是甲对修了五分之三,如果甲独修7天完成,那么乙队单独修要几天完成?
张师傅加工一批零件,原打算每天做50个,为了提早10天完成,他把效率提高,每天做75个,问张师傅要再做多少天?【用方程解,要设,列出方程式】
加工一批零件,师傅单独要15天完成,徒弟单独做要24天完成。现在土地单独先做了若干天,再由师傅单独经过5天才完成任务。土地单独先做了多少天?
有两筐苹果,第二匡比第一筐少四分之一,从第二筐那座4.2kg后,第一筐与第二筐的比是8:5.第一筐苹果比原来第二筐苹果多多少千克?
甲乙二人在圆形跑道上跑步,已知甲的速度比乙快,如果二人在同一地方同时出发,同向跑,则经过3分20秒可以相遇一次;若反向跑,则经过40秒也可以第一次相遇,已知甲跑步的速度每秒跑6米,这个圆形跑道的直径有多少米?【圆周率取3】
my first letter is in 'tea' ,not in 'sea' my second letter is in 'those' ,not in 'these' my third请才醋意中绿色食品。列算式,并作答。甲乙两队同时合修一条公路,修完是甲对修了五分之三,如果甲独修7天完
(1)设总路程为 1 则甲的工作效率为1/7,当甲乙合作时,已知甲修了3/5,则甲修了21/5天,则乙队也修了21/5天,又因为甲乙和修时,乙修了2/5,所以乙的工作效率为2/21,所以乙单独修需要10.5天.
(2)你问题好像打错了吧,你再看看
(3)设徒弟做了x天
1/24*X+(1/15)*5=1
X=16
(4)设第一筐苹果有X千克
则;X:3/4X-4.2=8:5
X=33.6
则第二筐苹果有22.2千克
则多11.4千克
(5)设乙的速度为X,圆形跑道的直径为Y
则:{40(X+6)=3y
{1200-200X =3y
解得;{X=4
{Y=400/3
即圆形跑道的直径为400/3米
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