作业帮[(2.74-0.56)*(29/12-79/60+2.275)]/(20/17)
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/14 09:01:11
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[(2.74-0.56)*(29/12-79/60+2.275)]/(20/17)
[(2.74-0.56)*(29/12-79/60+2.275)]/(20/17)
[(2.74-0.56)*(29/12-79/60+2.275)]/(20/17)
=2.18*(145/60-79/60+2.275)*(17/20)
=2.18*(66/60+2.275)*17/20
=2.18*(1.1+2.275)*17/20
=2.18*3.375*17/20
=6.253875
[(2.74-0.56)*(29/12-79/60+2.275)]/(20/17)
[(2.74-0.56)*(29/12-79/60+2.275)]/(20/17)
0.56×2.74+2.74×0.44过城
{2.74-0.56*(2又5/12-1又19/60+2.275)}/1又3/17
能简算的要简算：[2.74-0.56×(2又5/12-1又19/60+2.275)]÷17/20
12/29
已知两地的标高为2.74和0.465,水平长度为12,求坡度,
29分之12
如果12/29
5.6乘8.8加0.56乘12的简便运算
12*29+12简便运算
16/29*12+17/29*16简算
1.99又12分之71乘（-36）2.74乘（-1280）-74乘（-1140）-（-74）乘141
0.56*99+0.56
29分之20×12+29分之12×9=
12乘29等于几
11+12+13+14+.+29
29/27-23/11+29/21-23/12