已知x-2y=3,x²-2xy+4y²=11,求下列各值; (1)xy (2)x²-2xy²顺便帮我把因式分解也解决一下:-x²+4x-4 4x³-4²y-(x-y)
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![已知x-2y=3,x²-2xy+4y²=11,求下列各值; (1)xy (2)x²-2xy²顺便帮我把因式分解也解决一下:-x²+4x-4 4x³-4²y-(x-y)](/uploads/image/z/1064230-70-0.jpg?t=%E5%B7%B2%E7%9F%A5x-2y%3D3%2Cx%26%23178%3B-2xy%2B4y%26%23178%3B%3D11%2C%E6%B1%82%E4%B8%8B%E5%88%97%E5%90%84%E5%80%BC%EF%BC%9B+%EF%BC%881%EF%BC%89xy+%EF%BC%882%EF%BC%89x%26%23178%3B-2xy%26%23178%3B%E9%A1%BA%E4%BE%BF%E5%B8%AE%E6%88%91%E6%8A%8A%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E4%B9%9F%E8%A7%A3%E5%86%B3%E4%B8%80%E4%B8%8B%EF%BC%9A-x%26%23178%3B%2B4x-4+4x%26%23179%3B-4%26%23178%3By-%EF%BC%88x-y%EF%BC%89)
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已知x-2y=3,x²-2xy+4y²=11,求下列各值; (1)xy (2)x²-2xy²顺便帮我把因式分解也解决一下:-x²+4x-4 4x³-4²y-(x-y)
已知x-2y=3,x²-2xy+4y²=11,求下列各值; (1)xy (2)x²-2xy²
顺便帮我把因式分解也解决一下:-x²+4x-4 4x³-4²y-(x-y)
已知x-2y=3,x²-2xy+4y²=11,求下列各值; (1)xy (2)x²-2xy²顺便帮我把因式分解也解决一下:-x²+4x-4 4x³-4²y-(x-y)
x-2y=3,
两边平方,
x²-4xy+4y²=9 (1)
x²-2xy+4y²=11 (2)
两式相减,
2xy=2
xy=1
x²y-2xy² 这题是不是少了y
=xy(x-2y)
=1×3
=3
因式分解:
-x²+4x-4
=-(x²-4x+4)
=-(x-2)²
4x³-4x²y-(x-y)
=4x²(x-y)-(x-y)
=(x-y)(4x²-1)
=(x-y)(2x+1)(2x-1)