a,b,c是有理数且|a|=1|b-2|+(3a+2c)^2=0求abc/a+b+c=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 21:09:01
![a,b,c是有理数且|a|=1|b-2|+(3a+2c)^2=0求abc/a+b+c=?](/uploads/image/z/1070518-22-8.jpg?t=a%2Cb%2Cc%E6%98%AF%E6%9C%89%E7%90%86%E6%95%B0%E4%B8%94%7Ca%7C%3D1%7Cb-2%7C%2B%EF%BC%883a%2B2c%EF%BC%89%5E2%3D0%E6%B1%82abc%2Fa%2Bb%2Bc%3D%3F)
x)KII~6c9'=Ɏ)555IF5t'j%gdklcSbR~vvMR>eP
Og/xcsaI=Own~6mO,N i::IF:ɶF:@6*7^Y4]3}S<;Ԏu
a,b,c是有理数且|a|=1|b-2|+(3a+2c)^2=0求abc/a+b+c=?
a,b,c是有理数且|a|=1|b-2|+(3a+2c)^2=0求abc/a+b+c=?
a,b,c是有理数且|a|=1|b-2|+(3a+2c)^2=0求abc/a+b+c=?
因为绝对值和平方都大于等于0,所以a=1,-1,b=2,c=-3/2,3/2
所以abc/a+b+c=-2或-6/5