已知有理数a,b,c满足丨a-1丨+丨b+3丨+丨3c-1丨=0求(abc)的2013次方÷(a÷(a的9次方×b的2次方×c的2次方
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![已知有理数a,b,c满足丨a-1丨+丨b+3丨+丨3c-1丨=0求(abc)的2013次方÷(a÷(a的9次方×b的2次方×c的2次方](/uploads/image/z/1070530-34-0.jpg?t=%E5%B7%B2%E7%9F%A5%E6%9C%89%E7%90%86%E6%95%B0a%2Cb%2Cc%E6%BB%A1%E8%B6%B3%E4%B8%A8a-1%E4%B8%A8%2B%E4%B8%A8b%2B3%E4%B8%A8%2B%E4%B8%A83c-1%E4%B8%A8%3D0%E6%B1%82%28abc%29%E7%9A%842013%E6%AC%A1%E6%96%B9%C3%B7%28a%C3%B7%EF%BC%88a%E7%9A%849%E6%AC%A1%E6%96%B9%C3%97b%E7%9A%842%E6%AC%A1%E6%96%B9%C3%97c%E7%9A%842%E6%AC%A1%E6%96%B9)
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已知有理数a,b,c满足丨a-1丨+丨b+3丨+丨3c-1丨=0求(abc)的2013次方÷(a÷(a的9次方×b的2次方×c的2次方
已知有理数a,b,c满足丨a-1丨+丨b+3丨+丨3c-1丨=0求(abc)的2013次方÷(a
÷(a的9次方×b的2次方×c的2次方
已知有理数a,b,c满足丨a-1丨+丨b+3丨+丨3c-1丨=0求(abc)的2013次方÷(a÷(a的9次方×b的2次方×c的2次方
因为绝对值大于等于零,所以三个绝对值均为零时结果才能为零
即丨a-1丨=0 丨b+3丨=0 丨3c-1丨=0
解得 a=1 b= -3 c = 1/3
故 a^9 = 1 b^3 = 9 c^2= 1/9
abc = -3 a^9 * b^2 * c^2= 1 *9* 1/9 = 1
故(abc)^2013 /(a^9 * b^2* c^2) = (-3)^2013 /1
= (-3)^2013