C# 斐波那契数列 兔子繁殖int x = 0,y = 1; for (int j = 1; j < 10; j++,y = x + y,x = y - x) Console.Write(y + " ")(int j = 1; j < 10; j++,y = x + y,x = y - x)
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![C# 斐波那契数列 兔子繁殖int x = 0,y = 1; for (int j = 1; j < 10; j++,y = x + y,x = y - x) Console.Write(y +](/uploads/image/z/1071656-8-6.jpg?t=C%23+%E6%96%90%E6%B3%A2%E9%82%A3%E5%A5%91%E6%95%B0%E5%88%97+%E5%85%94%E5%AD%90%E7%B9%81%E6%AE%96int+x+%3D+0%2Cy+%3D+1%3B+for+%28int+j+%3D+1%3B+j+%3C+10%3B+j%2B%2B%2Cy+%3D+x+%2B+y%2Cx+%3D+y+-+x%29+Console.Write%28y+%2B+%22+%22%29%28int+j+%3D+1%3B+j+%3C+10%3B+j%2B%2B%2Cy+%3D+x+%2B+y%2Cx+%3D+y+-+x%29)
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C# 斐波那契数列 兔子繁殖int x = 0,y = 1; for (int j = 1; j < 10; j++,y = x + y,x = y - x) Console.Write(y + " ")(int j = 1; j < 10; j++,y = x + y,x = y - x)
C# 斐波那契数列 兔子繁殖
int x = 0,y = 1;
for (int j = 1; j < 10; j++,y = x + y,x = y - x)
Console.Write(y + " ")
(int j = 1; j < 10; j++,y = x + y,x = y - x)
C# 斐波那契数列 兔子繁殖int x = 0,y = 1; for (int j = 1; j < 10; j++,y = x + y,x = y - x) Console.Write(y + " ")(int j = 1; j < 10; j++,y = x + y,x = y - x)
hawk1415926 ,
这是循环语句,具体的意思是,数列前两项为,0,1,这是数列初始值,J作为月下标,他要找前十个月的兔子数量,当数列下列增加一项,那么,这一项的具体值就等于前面两个之和,然后那个X等于新得的具体值减去前前面一项,就得到于新值前面的一个值,这样,计算就往后移动了一步.希望我讲明白了啊.