用因式分解法解释下列方程(2a-1)^2=0(2x-5)^2=94x^2-(x-1)^2=0

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/24 10:40:30
用因式分解法解释下列方程(2a-1)^2=0(2x-5)^2=94x^2-(x-1)^2=0
x){>e bgɗ]Ovt?l+5u 5l 4*tMA,K8#] MR>QF"̃rah&Pՙ U:z5&PP& 6J$A]h t_dzl{ɎUϦnx>@;Ŗ:ϦBܢ4H-0tn72j arP+:` 2,n0h xh?

用因式分解法解释下列方程(2a-1)^2=0(2x-5)^2=94x^2-(x-1)^2=0
用因式分解法解释下列方程
(2a-1)^2=0
(2x-5)^2=9
4x^2-(x-1)^2=0

用因式分解法解释下列方程(2a-1)^2=0(2x-5)^2=94x^2-(x-1)^2=0
2a-1=0,a=0.5
(2x-5+3)(2x-5-3)=0,x=1,4
(2x+x-1)(2x-x+1)=0,x=1/3,-1

(2a-1)^2=0很显然一个数的平方非负,故2a-1=0 a=1/2,
(2x-5)^2=9,4x^2-20x+16=0,(x-1)(x-4)=0,故x=1或4
4x^2-(x-1)^2=0,(2x+x-1)(2x-x+1)=0,(3x-1)(x+1)=0,故x=1/3或-1