已知x/(x²-3x+1=7),求x²/(x^4+x²+1)的值
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已知x/(x²-3x+1=7),求x²/(x^4+x²+1)的值
已知x/(x²-3x+1=7),求x²/(x^4+x²+1)的值
已知x/(x²-3x+1=7),求x²/(x^4+x²+1)的值
即x=7x²-21x+7
7x²+7=22x
两边平方
49x⁴+98x²+49=484x²
两边减去49x²
49(x⁴+x²+1)=435x²
所以原式=49/435