1.曲线y=x/(1-x^2)的渐近线有?2.ysinx+e^y-x=1确定y=y(x)的隐函数,则导数值y'(0)=

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/06 07:04:13
1.曲线y=x/(1-x^2)的渐近线有?2.ysinx+e^y-x=1确定y=y(x)的隐函数,则导数值y'(0)=
xŒOKAJ ܱC I^fnYH%1`wgN]Dwyg淬ObM4t-O֣+ds4f*%nwydfzO+hɊ- $')!'~omA7nCGOGlց6jx2^-"WI*Gn:*J 0矅J0H$*&0=#sp(CkAK ^ANݹ j q4}{~ví*~Y* 8 Vu,M}X3B~#[`:V+ӱ*Xa@KF'=x

1.曲线y=x/(1-x^2)的渐近线有?2.ysinx+e^y-x=1确定y=y(x)的隐函数,则导数值y'(0)=
1.曲线y=x/(1-x^2)的渐近线有?2.ysinx+e^y-x=1确定y=y(x)的隐函数,则导数值y'(0)=

1.曲线y=x/(1-x^2)的渐近线有?2.ysinx+e^y-x=1确定y=y(x)的隐函数,则导数值y'(0)=
1.曲线y=x/(1-x²)的渐近线有?
y=x/(1-x²)=x/(1+x)(1-x),因此有x=1和x=-1两条垂直渐近线;
又x➔∞limx/(1-x²)=0,故有一条水平渐近线y=0;
2.ysinx+e^y-x=1确定y=y(x)的隐函数,则导数值y'(0)=?
F(x,y)=ysinx+e^y-x-1=0
dy/dx=-(∂F/∂x)/(∂F∂y)=-(ycosx-1)/(sinx+e^y).(1);
将x=0代入原式得e^y=1,故有y=0;将(0,0)代入(1)式即得:y′(0)=1.

1.x=1,x=-1,y=0
2.y'(0)=0.5