已知(a-1)²+[2- b]=0求[(a-2 b)(a+2b)-(-a+2b)(-a+2 b)]÷(-4 b)

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已知(a-1)²+[2- b]=0求[(a-2 b)(a+2b)-(-a+2b)(-a+2 b)]÷(-4 b)
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已知(a-1)²+[2- b]=0求[(a-2 b)(a+2b)-(-a+2b)(-a+2 b)]÷(-4 b)
已知(a-1)²+[2- b]=0求[(a-2 b)(a+2b)-(-a+2b)(-a+2 b)]÷(-4 b)

已知(a-1)²+[2- b]=0求[(a-2 b)(a+2b)-(-a+2b)(-a+2 b)]÷(-4 b)
(a-1)²+▕2- b▏=0
a-1=0,2- b=0
a=1,b=2
,[(a-2 b)(a+2b)-(-a+2b)(-a+2 b)]÷(-4 b)
=[(a-2 b)(a+2b)-(a-2b)(a-2 b)]÷(-4 b)
=(a-2 b)[(a+2b)-(a-2b)]÷(-4 b)
=(a-2 b)×4b÷(-4 b)
=2b-a=2×2-1=3