(1/a+1/b)²÷(1/a²-1/b²)

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(1/a+1/b)²÷(1/a²-1/b²)
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(1/a+1/b)²÷(1/a²-1/b²)
(1/a+1/b)²÷(1/a²-1/b²)

(1/a+1/b)²÷(1/a²-1/b²)
=(1/a+1/b)²÷[(1/a+1/b)(1/a-1/b)]
=(1/a+1/b)/(1/a-1/b)
=(b+a)/(b-a)