初二关于电功率的物理题"220V 60W"的灯泡,接在110V的电路中,灯泡实际的功率是多大?如果按P=UI算.60W=220V*I则I=3/11A.再代入.P=UIP=110V*3/11AP=30W.这样算错在哪里?如果只使用P=UI或P=W/T这两道公式,(因为
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 13:26:05
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