化简sin²(a-π/2)/cos(a-3π)sin(3π/2+a).
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化简sin²(a-π/2)/cos(a-3π)sin(3π/2+a).
化简sin²(a-π/2)/cos(a-3π)sin(3π/2+a)
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化简sin²(a-π/2)/cos(a-3π)sin(3π/2+a).
sin²(a-π/2)=cos²a
cos(a-3π)*sin(3π/2+a)=-cosa * (-cosa)=cos²a
所以sin²(a-π/2)/cos(a-3π)sin(3π/2+a)=1