ab=ad,ac=ae,∠bad=∠cae,试说明be=cd

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ab=ad,ac=ae,∠bad=∠cae,试说明be=cd
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ab=ad,ac=ae,∠bad=∠cae,试说明be=cd
ab=ad,ac=ae,∠bad=∠cae,试说明be=cd

ab=ad,ac=ae,∠bad=∠cae,试说明be=cd
这没图吗.

因为∠BAD=∠CAE,

所以∠BAD+∠BAC=∠CAE+∠BAC

得到∠DAC=∠EAB

又AD=AE,AC=AB

所以三角形DAC全等于三角形EAB

所以CD=BE