(a-2\1)²(a²+4\1)²(a+2\1)²
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(a-2\1)²(a²+4\1)²(a+2\1)²
(a-2\1)²(a²+4\1)²(a+2\1)²
(a-2\1)²(a²+4\1)²(a+2\1)²
[(a-1/2)(a+1/2)(a²+1/4)]²
=[(a²-1/4)(a²+1/4)]²
=(a的4次方-1/16)²
=a的8次方-1/8a的4次方+1/256