化简 {sin(π+α)cos(α-2π)tan9π/4}/sin(-α)sin(7π/2+α)过程

化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α) [sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简 化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α) (1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 （3/2*π 2sinα*cosα*cos(2π-α)+cos(π+2α)*cosα*tanα化简! 若cosα>sinα,(-π/2 化简[sin(π/2-α）cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π+α) 化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π) 化简sin(α-2π)+sin(-a-3π)cos(α-3π)/cos(π-α)-cos(-π-α)cos(α-4π) 化简：2sin（π+α）cos（π-α） 化简cos(3/2π+π)sin(-π+α) 化简[tan(2π-α)sin(-2π-α)cos(6π-α)]/[cos(α-π)sin(5π-α)] 化简tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α) 化简：[ cos(α-π/2)/sin(5π/2+α) ] ×sin(α-2π) × cos（2π-α）RT. 化简：[1+2sin(α+2π)*cos(α-2π)]/[sin(α+4π)+cos(α+8π)] 化简sin(α-3/2π)cos(α-π)-sin(α-2π)cos(α-π/2)=? 化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)= 化简［sin(2π-α)cos(π+α)cos(π/2+α)cos(11π/2-α)］/［cos(π-α)sin(π+α)sin(-π-α)sin［（...化简［sin(2π-α)cos(π+α)cos(π/2+α)cos(11π/2-α)］/［cos(π-α)sin(π+α)sin(-π-α)sin［（9π/2）+α］］