若f(x+y,x-y)=x2-y2,则f(x,y)=,

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若f(x+y,x-y)=x2-y2,则f(x,y)=,
若f(x+y,x-y)=x2-y2,则f(x,y)=,

若f(x+y,x-y)=x2-y2,则f(x,y)=,
f(x+y,x-y)=x^2-y^2=(x+y)(x-y)
令x+y=a,x-y=b
那么f(a,b)=ab
所以f(x,y)=xy

已知，
f(x+y,x-y)=x²-y²=(x+y)(x-y)
所以，
f(x,y)=xy

设 u=x+y,v=x-y
f(u,v)=f(x+y,x-y)=x^2-y^2=(x+y)(x-y)=uv
得f(x,y)=xy

f（x，y）=xy

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