已知函数f(x)=x²-(k+3)x+(2k-1)(1)判断函数f(x)的零点个数(2)若函数f(x)的两个零点都大于1,求k的取值范围(3)若函数在区间(-1,1)内有零点,求k的取值范围
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![已知函数f(x)=x²-(k+3)x+(2k-1)(1)判断函数f(x)的零点个数(2)若函数f(x)的两个零点都大于1,求k的取值范围(3)若函数在区间(-1,1)内有零点,求k的取值范围](/uploads/image/z/10793386-10-6.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dx%26%23178%3B-%EF%BC%88k%2B3%EF%BC%89x%2B%EF%BC%882k-1%EF%BC%89%EF%BC%881%EF%BC%89%E5%88%A4%E6%96%AD%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E9%9B%B6%E7%82%B9%E4%B8%AA%E6%95%B0%EF%BC%882%EF%BC%89%E8%8B%A5%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E4%B8%A4%E4%B8%AA%E9%9B%B6%E7%82%B9%E9%83%BD%E5%A4%A7%E4%BA%8E1%2C%E6%B1%82k%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%EF%BC%883%EF%BC%89%E8%8B%A5%E5%87%BD%E6%95%B0%E5%9C%A8%E5%8C%BA%E9%97%B4%EF%BC%88-1%2C1%EF%BC%89%E5%86%85%E6%9C%89%E9%9B%B6%E7%82%B9%2C%E6%B1%82k%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4)
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