计算:4cos30°sin60°+(-2)^-1-(√2009-√2008)^0

来源:学生作业帮助网 编辑:作业帮 时间:2024/08/01 19:28:16
计算:4cos30°sin60°+(-2)^-1-(√2009-√2008)^0
x){nue_llphCqf5Ҍ5x1RB[h$铧QΆ;IUokeokoTdrl 젮s0]@c7z~O7P^C@/d 4A(@5)܏(H

计算:4cos30°sin60°+(-2)^-1-(√2009-√2008)^0
计算:4cos30°sin60°+(-2)^-1-(√2009-√2008)^0

计算:4cos30°sin60°+(-2)^-1-(√2009-√2008)^0
4cos30°sin60°+(-2)^-1-(√2009-√2008)^0
=4*3/4-1/2-1-1
=1/2

原式=4×(√3/2)×(√3/2)+(-1/2)-1
=4×3/4-1/2-1
=3-1/2-1
=3/2