如图,已知AE交BC于点D,角1=角2=角3,AB=AD,求证:DC=BE.(要有详细的过程和依据,否则不采纳.)
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![如图,已知AE交BC于点D,角1=角2=角3,AB=AD,求证:DC=BE.(要有详细的过程和依据,否则不采纳.)](/uploads/image/z/1082304-0-4.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5AE%E4%BA%A4BC%E4%BA%8E%E7%82%B9D%2C%E8%A7%921%3D%E8%A7%922%3D%E8%A7%923%2CAB%3DAD%2C%E6%B1%82%E8%AF%81%EF%BC%9ADC%3DBE.%EF%BC%88%E8%A6%81%E6%9C%89%E8%AF%A6%E7%BB%86%E7%9A%84%E8%BF%87%E7%A8%8B%E5%92%8C%E4%BE%9D%E6%8D%AE%2C%E5%90%A6%E5%88%99%E4%B8%8D%E9%87%87%E7%BA%B3.%EF%BC%89)
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如图,已知AE交BC于点D,角1=角2=角3,AB=AD,求证:DC=BE.(要有详细的过程和依据,否则不采纳.)
如图,已知AE交BC于点D,角1=角2=角3,AB=AD,求证:DC=BE.(要有详细的过程和依据,否则不采纳.)
如图,已知AE交BC于点D,角1=角2=角3,AB=AD,求证:DC=BE.(要有详细的过程和依据,否则不采纳.)