1.若x²-12x+m=(x+n)²,则m-n=a.30 b.36 c.42 d.482.用配方法解一元二次方程x²-2x-m=0配方后的方程是a.(x+1)²=m²+1b.(x-1)²=m-1c.(x-1)²=1-md.(x-1)²=m+1
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![1.若x²-12x+m=(x+n)²,则m-n=a.30 b.36 c.42 d.482.用配方法解一元二次方程x²-2x-m=0配方后的方程是a.(x+1)²=m²+1b.(x-1)²=m-1c.(x-1)²=1-md.(x-1)²=m+1](/uploads/image/z/1082427-51-7.jpg?t=1.%E8%8B%A5x%26%23178%3B-12x%2Bm%3D%28x%2Bn%29%26%23178%3B%2C%E5%88%99m-n%3Da.30+b.36+c.42+d.482.%E7%94%A8%E9%85%8D%E6%96%B9%E6%B3%95%E8%A7%A3%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bx%26%23178%3B-2x-m%3D0%E9%85%8D%E6%96%B9%E5%90%8E%E7%9A%84%E6%96%B9%E7%A8%8B%E6%98%AFa.%28x%2B1%29%26%23178%3B%3Dm%26%23178%3B%2B1b.%28x-1%29%26%23178%3B%3Dm-1c.%28x-1%29%26%23178%3B%3D1-md.%28x-1%29%26%23178%3B%3Dm%2B1)
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1.若x²-12x+m=(x+n)²,则m-n=a.30 b.36 c.42 d.482.用配方法解一元二次方程x²-2x-m=0配方后的方程是a.(x+1)²=m²+1b.(x-1)²=m-1c.(x-1)²=1-md.(x-1)²=m+1
1.若x²-12x+m=(x+n)²,则m-n=
a.30 b.36 c.42 d.48
2.用配方法解一元二次方程x²-2x-m=0配方后的方程是
a.(x+1)²=m²+1
b.(x-1)²=m-1
c.(x-1)²=1-m
d.(x-1)²=m+1
1.若x²-12x+m=(x+n)²,则m-n=a.30 b.36 c.42 d.482.用配方法解一元二次方程x²-2x-m=0配方后的方程是a.(x+1)²=m²+1b.(x-1)²=m-1c.(x-1)²=1-md.(x-1)²=m+1
1 m=36,n=-6
m-n=42,选C
2 B没法解释,不行就展开比较一下~