若x²+y²+5/4=2x+y,求xy/(x+y)(详解)

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若x²+y²+5/4=2x+y,求xy/(x+y)(详解)
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若x²+y²+5/4=2x+y,求xy/(x+y)(详解)
若x²+y²+5/4=2x+y,求xy/(x+y)(详解)

若x²+y²+5/4=2x+y,求xy/(x+y)(详解)
x^2+y^2-2x-y+5/4=0
配方:(x-1)^2-1+(y-1/2)^2-1/4+5/4=0
得x=1 y=1//2
xy/(x+y)=1/3

原式可整理为:(x-1)^2 +(y-1/2)^2 = 0
所以 x=1, y=1/2
所以xy/(x+y) = 1/3

-1 (x-1)^2+(y+1/2)^2=0 所以x=1 y=-1/2