先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1x²-3x-4/(x²+2x+1)这个地方怎么化简?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/08 21:26:36
![先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1x²-3x-4/(x²+2x+1)这个地方怎么化简?](/uploads/image/z/1088162-26-2.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%2C%E5%86%8D%E6%B1%82%E5%80%BCx-4%2F%28x%26%23178%3B-1%29%E9%99%A4%E4%BB%A5x%26%23178%3B-3x-4%2F%28x%26%23178%3B%2B2x%2B1%29%2B1%2F%28x-1%29%2C%E5%85%B6%E4%B8%ADx%3D2%E5%80%8D%E6%A0%B9%E5%8F%B73%2B1x%26%23178%3B-3x-4%2F%28x%26%23178%3B%2B2x%2B1%29%E8%BF%99%E4%B8%AA%E5%9C%B0%E6%96%B9%E6%80%8E%E4%B9%88%E5%8C%96%E7%AE%80%3F)
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先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1x²-3x-4/(x²+2x+1)这个地方怎么化简?
先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1
x²-3x-4/(x²+2x+1)这个地方怎么化简?
先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1x²-3x-4/(x²+2x+1)这个地方怎么化简?
x²-3x-4/(x²+2x+1)
=(x-4)(x+1)/(x+1)^2
=(x-4)/(x+1)