a>0,b>0,a≠b,比较p=(a^k+1)+(b^k+1),Q=(ab^k)+(a^k)b,k属于N
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a>0,b>0,a≠b,比较p=(a^k+1)+(b^k+1),Q=(ab^k)+(a^k)b,k属于N
a>0,b>0,a≠b,比较p=(a^k+1)+(b^k+1),Q=(ab^k)+(a^k)b,k属于N
a>0,b>0,a≠b,比较p=(a^k+1)+(b^k+1),Q=(ab^k)+(a^k)b,k属于N
p-q=a^(k+1)+b^(k+1)-ab^k -ba^k
=a^k(a-b)+b^k(b-a)
=(a^k-b^k)(a-b)
,k属于N
如果 a>b
a^k>b^k 上面那个是 正数,p>q
如果aq