因式分解(3道)用“十字相乘法”x^3-5x^2y-24xy^2x^3-3x^2-10x(x^2+4x)^2-x^2-4x-20

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/27 19:03:05
因式分解(3道)用“十字相乘法”x^3-5x^2y-24xy^2x^3-3x^2-10x(x^2+4x)^2-x^2-4x-20
x){:{=O;^,_~Ot>QÜON>{Ǔ3manEiEQIEeo Thim M $bRkd`T .{a6Z_`gCkRڂ5%@@QMEFq&oPWtA[$]lm  B~qAb4mC=,7pn<

因式分解(3道)用“十字相乘法”x^3-5x^2y-24xy^2x^3-3x^2-10x(x^2+4x)^2-x^2-4x-20
因式分解(3道)
用“十字相乘法”
x^3-5x^2y-24xy^2
x^3-3x^2-10x
(x^2+4x)^2-x^2-4x-20

因式分解(3道)用“十字相乘法”x^3-5x^2y-24xy^2x^3-3x^2-10x(x^2+4x)^2-x^2-4x-20
x^3-5x^2y-24xy^2
=x(x^2-5xy-24y^2)
=x(x-8y)(x+3y)
x^3-3x^2-10x
=x(x^2-3x-10)
=x(x-5)(x+2)
(x^2+4x)^2-x^2-4x-20
=(x^2+4x)^2-(x^2+4x)-20
=(x^2+4x-5)(x^2+4x+4)
=(x+5)(x-1)(x+2)^2

1.=x(x-8y)(x+3y)
2.=x(x-5)(x+2)
3.=(x^2+4x-5)(x^2+4x+4)
=(x+5)(x-1)(x+2)^2