在三角形ABC中,a=0.15,C=103.4度,B=75.85度.求c的长?

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在三角形ABC中,a=0.15,C=103.4度,B=75.85度.求c的长?
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在三角形ABC中,a=0.15,C=103.4度,B=75.85度.求c的长?
在三角形ABC中,a=0.15,C=103.4度,B=75.85度.求c的长?

在三角形ABC中,a=0.15,C=103.4度,B=75.85度.求c的长?
A=180-103.4-75.85=0.75
a/sinA=c/sinC
c=asinC/sinA
=0.15sin103.4/sin0.75
=0.15x0.97277587820939656628059743687412/0.013089595571344440190284209702852
=0.14591638173140948494208961553112/0.013089595571344440190284209702852
=11.147508793231747350229417687645

求得角A=0.75度,由正弦定理,a/sinA = c/sinC ;求得c=11.15