求lim n趋向于无穷 n(n^1/n -1)/ln n
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/19 22:36:36
xJ0_% 8-Tڬ,} 5"[]Ht2Q0IU_vMι7˱ry6.@ mlM'a;zgZ\
~MӓG7Rn;ւbzo(iPTATH4|@M&cK)k&3eAd([+ajUVgpp0SQXK4
fkxsk[~e|γɩ}O}7AU
求lim n趋向于无穷 n(n^1/n -1)/ln n
求lim n趋向于无穷 n(n^1/n -1)/ln n
求lim n趋向于无穷 n(n^1/n -1)/ln n
令t=1/n 则:t→0
lim n(n^1/n -1)/ln n
=lim﹣(1/t^t -1)/tlnt
=lim(1- 1/t^t )/lnt^t
∵t→0
∴可求 t→0时,t^t 极限为 1
令x=t^t,则x→1
∴原始化为:
lim(1- 1/x)/lnx (0/0型,用罗比达法则)
=lim(1- 1/x)'/(lnx)'
=lim(1/x²)/(1/x)
=lim1/x
=1
综上,原式极限为 1
求lim(n趋向于正无穷)(x^n)/n!
求lim n趋向于无穷 n(n^1/n -1)/ln n
lim(n/(n^2+1)+...+n/(n^2+n))x趋向于无穷 求解答过程~
求极限:Lim(1+1/n-1/n^2)^n n趋向于正无穷
求极限 n趋向于无穷 lim((根号下n^2+1)/(n+1))^n
求极限lim(n趋向于无穷)(n+1)(根号下(n^2+1)-n)
求lim趋向于无穷3^n+(-2)^n/3^(n+1)+(-2)^(n+1)
求极限lim n趋向于无穷(1/n)*√(n+1)(n+2)⋯(n+n)
lim根号n*n+n除以n+1=?(档n趋向于无穷)
lim n趋向于无穷 n[((n+1)/n)^n-e]
lim(2^n+3^n)^1
(n趋向无穷)
lim[(根号下n^2+n)-n],n趋向于无穷,求函数的极限
求极限lim√[(n²+n)-n],n趋向于无穷.
求当n趋向于无穷时,lim[cos(θ/n)])^n)^n=?
判断极限是否存在lim [n+(-1)^n]/n n趋向于无穷 lim |x|/x x趋向于0
lim x趋向于无穷 (2^n+1+3^n+1)/(2^n+3^n)=
求极限过程,求救:x趋向于无穷,lim(1/n^2+2/n^2+……+n/n^2)
求极限lim n趋向于无穷(1/n)*n次方根下(n+1)(n+2)⋯(n+n)