用适当的方法解以下8个一元二次方程x²+2x=3x(x+1)2x²-2√6 x+3=0x²-(1+2+2√3)x+3+√3=0x²-4ax-4a²=0(a>0)2(x²-5)=x(1-x)4(3x-1)²=3(3x-1)p(p-8)-3p+24=0(2x²+3x)²-4(2x²+3)-5=0
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![用适当的方法解以下8个一元二次方程x²+2x=3x(x+1)2x²-2√6 x+3=0x²-(1+2+2√3)x+3+√3=0x²-4ax-4a²=0(a>0)2(x²-5)=x(1-x)4(3x-1)²=3(3x-1)p(p-8)-3p+24=0(2x²+3x)²-4(2x²+3)-5=0](/uploads/image/z/10907937-9-7.jpg?t=%E7%94%A8%E9%80%82%E5%BD%93%E7%9A%84%E6%96%B9%E6%B3%95%E8%A7%A3%E4%BB%A5%E4%B8%8B8%E4%B8%AA%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bx%26%23178%3B%2B2x%3D3x%28x%2B1%292x%26%23178%3B-2%E2%88%9A6+x%2B3%3D0x%26%23178%3B-%281%2B2%2B2%E2%88%9A3%29x%2B3%2B%E2%88%9A3%3D0x%26%23178%3B-4ax-4a%26%23178%3B%3D0%28a%EF%BC%9E0%292%28x%26%23178%3B-5%29%3Dx%281-x%294%283x-1%29%26%23178%3B%3D3%283x-1%29p%28p-8%29-3p%2B24%3D0%282x%26%23178%3B%2B3x%29%26%23178%3B-4%282x%26%23178%3B%2B3%29-5%3D0)
用适当的方法解以下8个一元二次方程x²+2x=3x(x+1)2x²-2√6 x+3=0x²-(1+2+2√3)x+3+√3=0x²-4ax-4a²=0(a>0)2(x²-5)=x(1-x)4(3x-1)²=3(3x-1)p(p-8)-3p+24=0(2x²+3x)²-4(2x²+3)-5=0
用适当的方法解以下8个一元二次方程
x²+2x=3x(x+1)
2x²-2√6 x+3=0
x²-(1+2+2√3)x+3+√3=0
x²-4ax-4a²=0(a>0)
2(x²-5)=x(1-x)
4(3x-1)²=3(3x-1)
p(p-8)-3p+24=0
(2x²+3x)²-4(2x²+3)-5=0
用适当的方法解以下8个一元二次方程x²+2x=3x(x+1)2x²-2√6 x+3=0x²-(1+2+2√3)x+3+√3=0x²-4ax-4a²=0(a>0)2(x²-5)=x(1-x)4(3x-1)²=3(3x-1)p(p-8)-3p+24=0(2x²+3x)²-4(2x²+3)-5=0
1,x²+2x=3x²+3x,2x²+x=0,x(2x+1)=0,x=0 或 x=-1/2
2,(√2x)²-2*√2*√3x+(√3)²=0,(√2x-√3)²=0,√2x-√3=0,x=√6/3
3,x²-(1+2√3)x+3+√3=0,(x-√3)(x-(1+√3))=0,x=√3 或 x=1+√3
4,x²-4ax-(2a)²=0,(x-2a)²=0,x-2a=0,x=2a
5,2x²-10=x-x²,3x²+x-10=0,(3x-5)(x+2)=0,x=5/3 或 x=-2
6,3x-1=0 或 4(3x-1)=3,12x-4=3,12x=7
x=1/3 或 x=7/12
7,p²-8p-3p+24=0,p²-11p+24=0,(p-3)(p-8)=0,p=3 或 p=8
8,(2x²+3x+1)(2x²+3x-5)=0
2x²+3x+1=0 或 2x²+3x-5=0
(2x+1)(x+1)=0,(2x+5)(x-1)=0
x=-1/2,x=-1,x=-5/2,x=1