1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)…………1/(a+2009)(a+2010)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 02:04:06
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)…………1/(a+2009)(a+2010)
x)3OH66@1q55,#%XMR> (M 5f.a>.F>ٱ-.~e϶uلl= S+.-0$C 1X6`΋M/|= ~7{fF چP7׃\  qn$QӢahX,-E `Kr4hC ؂wx

1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)…………1/(a+2009)(a+2010)
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)…………1/(a+2009)(a+2010)

1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)…………1/(a+2009)(a+2010)
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)…………1/(a+2009)(a+2010)
=1/a-1/(a+1)+1/(a+1)-1/(a+2)+1/(a+2)-1/(a+3)…………1/(a+2009)-1/(a+2010)
中间正负抵消
=1/a-1/(a+2010)
=2010/(a²+2010a)

裂项求和....
原式:=[1/a]-[1/a+1]+[1/a+1]-[1/a+2].....+[1/a+2009]-[1/a+2010]
=[1/a]-[1/a+2010]
=2010/[a(a+2010)]

[1/a(a+1)]+[1/(a+1)(a+2)]+[1/(a+2)(a+3)]......+[1/(a+2009)(a+2010)]
=1/a-1/(a+1)+1/(a+1)-1/(a+2)+1/(a+2)-1/(a+3)+......+1/(a+2009)-1/(a+2010)
=1/a-1/(a+2010)
=2010/[a(a+2010)]