先化简分式[(3x/x-1)-(x/1+x)]/(x/1-x²)再从不等式组{x-3(x-2)≥2 {4x-2<5x+1的解集中取一个合适的整数值代入,求原分式的值
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![先化简分式[(3x/x-1)-(x/1+x)]/(x/1-x²)再从不等式组{x-3(x-2)≥2 {4x-2<5x+1的解集中取一个合适的整数值代入,求原分式的值](/uploads/image/z/1103767-7-7.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%E5%88%86%E5%BC%8F%5B%EF%BC%883x%2Fx-1%29-%28x%2F1%2Bx%EF%BC%89%5D%2F%28x%2F1-x%26sup2%3B%EF%BC%89%E5%86%8D%E4%BB%8E%E4%B8%8D%E7%AD%89%E5%BC%8F%E7%BB%84%7Bx-3%28x-2%29%E2%89%A52+%7B4x-2%EF%BC%9C5x%2B1%E7%9A%84%E8%A7%A3%E9%9B%86%E4%B8%AD%E5%8F%96%E4%B8%80%E4%B8%AA%E5%90%88%E9%80%82%E7%9A%84%E6%95%B4%E6%95%B0%E5%80%BC%E4%BB%A3%E5%85%A5%2C%E6%B1%82%E5%8E%9F%E5%88%86%E5%BC%8F%E7%9A%84%E5%80%BC)
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先化简分式[(3x/x-1)-(x/1+x)]/(x/1-x²)再从不等式组{x-3(x-2)≥2 {4x-2<5x+1的解集中取一个合适的整数值代入,求原分式的值
先化简分式[(3x/x-1)-(x/1+x)]/(x/1-x²)
再从不等式组{x-3(x-2)≥2 {4x-2<5x+1的解集中取一个合适的整数值代入,求原分式的值
先化简分式[(3x/x-1)-(x/1+x)]/(x/1-x²)再从不等式组{x-3(x-2)≥2 {4x-2<5x+1的解集中取一个合适的整数值代入,求原分式的值
x-3x+6≥2
x≤2
4x-2<5x+1
x>-3
-3
=-(3x²+3x-x²+x)/(1-x²)×(1-x²)/x
=-(2x²+4x)/x
=-2x-4
分母不等于0
所以取x=2
原式=-4-4=-8