12 x^(2n+1)y^(m+1)- 20x^(n+1)y^ (2m+3)因式分解
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 13:38:49
x)34R06ԬR
F@!Qbb"}r>R[0XqE\)HU~qAbA R
12 x^(2n+1)y^(m+1)- 20x^(n+1)y^ (2m+3)因式分解
12 x^(2n+1)y^(m+1)- 20x^(n+1)y^ (2m+3)因式分解
12 x^(2n+1)y^(m+1)- 20x^(n+1)y^ (2m+3)因式分解
12 x^(2n+1)y^(m+1)- 20x^(n+1)y^ (2m+3)
=4x^(n+1)y^(m+1)(3x^n- 5y^ (m+2))
12 x^(2n+1)y^(m+1)- 20x^(n+1)y^ (2m+3)因式分解
提公因式法(过程)1、a(x-y)-b(x-y)2、a(x-y)-b(y-x)3、a(x-y)³-b(x-y)²4、4(x-y)³-8(y-x)²5、5(x-y)³+10(y-x)²6、6(m-n)³-12(n-m)7、m(m-n)+n(n-m)8、m(m-n
如果x^m-n×x^2n+1=x^11,y^m-1×y^4-n=y^5,求(-2)^m×(-1)^n的值
已知x^m+n=3,y^m-n=2,求代数式(-1/3x^2m+n·y^5m-6n)·(1/2x^m+2n·y^2n-m)
已知(m+n)x^n·y^m-2·(3xy^2+5x^2·y)=21x^m·y^n+1+35x^m+1·y^n,求m和n
分解因式:(1)5(x-y)³+10(y-x)² (2)mn(m-n)-m(n-m)分解因式:5(x-y)³+10(y-x)² (2)mn(m-n)-m(n-m)
已知2^=x,2^n=y,m,n都是正整数,m>=n,求2^m-n+1
2y(x-y)^2-(y-x)^3过程具体!(1)2y(x-y)^2-(y-x)^3(2)(m-n)^3+m(n-m)^2-n(m-n)^2
因式分解:(1)4(x-2)-2(2-x) (2)x^2(m-1)^2-4(1-m)^2 (3)-8x^2n+2y^n+2+12x^n+1y^2n+3(4)-m^2 n(x-y)^n+mn^2 (x-y)^n+1急急急急急急急,过程 (3)-8x^2n+2 y^n+2+12x^n+1 y^2n+3会几个打几个
1)x^2-y^2-x+四分之一2)9m^2-n^2+3m-n
(1)(m+n)^-4m(m+n)+4m^(2)a^+2a(b+c)+(b+c)^(3)4+12(x-y)+9(x-y)^(4)(a-b)(x-y)-(b-a)(x+y)
X^3*y^(m-1)*x^(m+y)*y^(2n+2)=x^9y^9
y-n = - (a-m)(x-m)/(b-n) .(1) (x-m)^2+(y-n)^2 = L^2 .(2) 求X,Y的值
若x^3y^m-1*x^m+n*y^2n+2=x^9y^9,则4m-3n=().
若3x^m+1y^2与x^3y^n的积是单项式3x^5y^5则n^m+m^n=
(1)(m+n)^3+2m(m+n)^2+m^2(m+n)= (2)[(x-2y)(x+2y)+4(1)(m+n)^3+2m(m+n)^2+m^2(m+n)=(2)[(x-2y)(x+2y)+4(x-y)^2]除以5x=(3)1.2345^2+(0.7655)^2+2.469乘0.7655-2.5^2=
数学一道分解因式计算题12x^(2m+1) y^(m+2)-20x^(n+1)y(2m+3)(n为正整数)不要一步到位
(1)x(x+y)(x-y)-x(x+y)²= (2)-7m(m-n)³+21mn(n-m)²