cos(a+贝塔)=1/5,cos(a-贝塔)=3/5,则tanatan贝塔=
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cos(a+贝塔)=1/5,cos(a-贝塔)=3/5,则tanatan贝塔=
cos(a+贝塔)=1/5,cos(a-贝塔)=3/5,则tanatan贝塔=
cos(a+贝塔)=1/5,cos(a-贝塔)=3/5,则tanatan贝塔=
解cos(a+β)=cosacosβ-sinasinβ=1/5
cos(a-β)=cosacosβ+sinasinβ=3/5
两式联立解得cosacosβ=2/5,sinasinβ=1/5
故tanatanβ
=(sinasinβ)/(cosacosβ)
=(1/5)/(2/5)
=1/2
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