化简:sin^(-α)-tan(360-α)tan(-α)-sin(180-α)cos(360-α)tan(180+α)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/24 14:53:21
x){3{fgiۨ[alf b`1X,9Y(
d$S0;*/o|~5O@:AjmAfCf-^$yt1$"LBr-
c u-¨g
Ov/}7F[
4t5J@,.[
L}X J26yvXs^rG
s`q~O磆fΎg-3f@h)! ʘJ
化简:sin^(-α)-tan(360-α)tan(-α)-sin(180-α)cos(360-α)tan(180+α)
化简:sin^(-α)-tan(360-α)tan(-α)-sin(180-α)cos(360-α)tan(180+α)
化简:sin^(-α)-tan(360-α)tan(-α)-sin(180-α)cos(360-α)tan(180+α)
用诱导公式
sin(-α)=-sinα
tan(360-α)=tan(-α)=-tanα
tan(-α)=-tanα
sin(180-α)=sinα
cos(360-α)=cos(-α)=cosα
tan(180+α)=tanα
所以原式=(-sinα)^2-(tanα)^2-sinαcosαtanα
=(sinα)^2-(tanα)^2-sinαcosα*sinα/cosα
=(sinα)^2-(tanα)^2-(sinα)^2
=-(tanα)^2
请问“sin^(-α)”是什么意思?
原式=(-sinα)^2-(tanα)^2-sinαcosαtanα
=(sinα)^2-(tanα)^2-sinαcosα*sinα/cosα
=(sinα)^2-(tanα)^2-(sinα)^2
=-(tanα)^2
化简:sin^(-α)-tan(360-α)tan(-α)-sin(180-α)cos(360-α)tan(180+α)
化简,cos²(-α)-tan(360°+α)/sin(-α)
化简cos^2(-α)-[tan(360°+α)/sin(-α)]
化简:tanα(cosα-sinα)+sinα(sinα+tanα)/1+cosα.
化简Sin(180-a)sin(270-a)tan(90-a)/Sin(90+a)tan(270+a)tan(360-a)
sinα>tanα
化简tanα(cosα-sinα)+(sinα+tanα)/(cotα+cscα)
化简tanα(cosα - sinα) + (sinα + tanα) / (cotα + cscα)
化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)
化简(sinα)/(1-cosα) *(根号((tanα-sinα)/(tanα+sinα)))化简(sinα)/(1-cosα)*(根号((tanα-sinα)/(tanα+sinα)))
化简:(sin²αtanα+cos²α/tanα+2sinαcosα)sinαcosα
化简tan(α+180度)+cos(-α)+cos(α+180度)分之sin(180度+α)-tan(-α)-tan(360度+α)
若sinαtanα
若sinα*tanα
证明三角恒等式tanαsinα/(tanα-sinα)=(tanα+sinα)/tanαsinα
证明:(tanα*sinα)/(tanα-sinα)=(tanα+sinα)/(tanα*sinα)
证明:(tanα*sinα)/(tanα-sinα)=(tanα+sinα)/(tanα*sinα)
求证(tanα·sinα)/(tanα-sinα)=(tanα+sinα)/(tanα·sinα)